वर्गमूल सर्पिल में यदि नया कर्ण \(\sqrt{82}\) बनता है, तो पिछले कर्ण की लंबाई क्या थी?
If the new hypotenuse formed in a square root spiral is \(\sqrt{82}\), what was the length of the previous hypotenuse?
Explanation opens after your attempt
Correct Answer
B. \(\sqrt{81}\)
Concept
If the new hypotenuse is \(\sqrt{n+1}\), the previous one is \(\sqrt{n}\). Therefore before \(\sqrt{82}\), it was \(\sqrt{81}\).
Why this answer is correct
The correct answer is B. \(\sqrt{81}\). If the new hypotenuse is \(\sqrt{n+1}\), the previous one is \(\sqrt{n}\). Therefore before \(\sqrt{82}\), it was \(\sqrt{81}\).
Exam Tip
नया कर्ण \(\sqrt{n+1}\) होता है तो पिछला कर्ण \(\sqrt{n}\) होता है। इसलिए \(\sqrt{82}\) से पहले \(\sqrt{81}\) था।
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