यदि वर्गमूल सर्पिल में किसी चरण पर नया कर्ण \(\sqrt{31}\) है, तो उससे ठीक पहले वाला कर्ण कौन-सा था?
If the new hypotenuse at a step in a square root spiral is \(\sqrt{31}\), which was the immediately previous hypotenuse?
Explanation opens after your attempt
Correct Answer
B. \(\sqrt{30}\)
Concept
If the new hypotenuse is \(\sqrt{n+1}\), the previous one is \(\sqrt{n}\). Therefore before \(\sqrt{31}\), it was \(\sqrt{30}\).
Why this answer is correct
The correct answer is B. \(\sqrt{30}\). If the new hypotenuse is \(\sqrt{n+1}\), the previous one is \(\sqrt{n}\). Therefore before \(\sqrt{31}\), it was \(\sqrt{30}\).
Exam Tip
नया कर्ण \(\sqrt{n+1}\) हो तो पिछला कर्ण \(\sqrt{n}\) होता है। इसलिए \(\sqrt{31}\) से पहले \(\sqrt{30}\) था।
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