यदि किसी नए त्रिभुज में कर्ण \(\sqrt{11}\) है और एक लंब भुजा (1) है, तो पिछली त्रिज्या कितनी थी?
If the hypotenuse of a new triangle is \(\sqrt{11}\) and one perpendicular side is (1), what was the previous radius?
Explanation opens after your attempt
Correct Answer
B. \(\sqrt{10}\)
Concept
The square of the previous radius is (11-1=10), so it was \(\sqrt{10}\). In reverse questions, subtract (1).
Why this answer is correct
The correct answer is B. \(\sqrt{10}\). The square of the previous radius is (11-1=10), so it was \(\sqrt{10}\). In reverse questions, subtract (1).
Exam Tip
पिछली त्रिज्या का वर्ग (11-1=10) होगा, इसलिए वह \(\sqrt{10}\) थी। उल्टे प्रश्नों में (1) घटाएं।
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