यदि सर्पिल में पहला कर्ण \(OB=\sqrt{2}\) है, तो \(\sqrt{10}\) तक पहुंचने के लिए (OB) के बाद कितने नए (1) इकाई वाले लंब चरण चाहिए?
If the first hypotenuse in the spiral is \(OB=\sqrt{2}\), how many new perpendicular steps of (1) unit are needed after (OB) to reach \(\sqrt{10}\)?
Explanation opens after your attempt
Correct Answer
C. (8)
Concept
From \(\sqrt{2}\) to \(\sqrt{10}\), the number under the root increases by (8), so (8) new steps are needed. Each step increases the inner number by (1).
Why this answer is correct
The correct answer is C. (8). From \(\sqrt{2}\) to \(\sqrt{10}\), the number under the root increases by (8), so (8) new steps are needed. Each step increases the inner number by (1).
Exam Tip
\(\sqrt{2}\) से \(\sqrt{10}\) तक वर्गमूल के अंदर संख्या (8) बढ़ती है, इसलिए (8) नए चरण चाहिए। हर चरण अंदर की संख्या को (1) बढ़ाता है।
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