यदि ((c+4)x-7+\(c^2-16\)x-5+21) की डिग्री (0) है, तो (c) का मान क्या है?

If the degree of ((c+4)x-7+\(c^2-16\)x-5+21) is (0), what is the value of (c)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. (c=-4)

Explanation

Simple Explanation

डिग्री (0) के लिए \(x^7\) और \(x^5\) दोनों पद हटने चाहिए। (c=-4) पर दोनों गुणांक (0) हो जाते हैं। / For degree (0), both \(x^7\) and \(x^5\) terms must vanish. At (c=-4), both coefficients become (0).

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि ((c+4)x-7+\(c^2-16\)x-5+21) की डिग्री (0) है, तो (c) का मान क्या है? / If the degree of ((c+4)x-7+\(c^2-16\)x-5+21) is (0), what is the value of (c)?

Correct Answer: B. (c=-4). Explanation: डिग्री (0) के लिए \(x^7\) और \(x^5\) दोनों पद हटने चाहिए। (c=-4) पर दोनों गुणांक (0) हो जाते हैं। / For degree (0), both \(x^7\) and \(x^5\) terms must vanish. At (c=-4), both coefficients become (0).