यदि \(t=\sqrt{5}+2\) है, तो \(t+\frac{1}{t}\) का मान क्या है?

If \(t=\sqrt{5}+2\), what is the value of \(t+\frac{1}{t}\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(2\sqrt{5}\)

Step 1

Concept

\(\frac{1}{\sqrt{5}+2}=\sqrt{5}-2\). Therefore the sum is \(2\sqrt{5}\).

Step 2

Why this answer is correct

The correct answer is A. \(2\sqrt{5}\). \(\frac{1}{\sqrt{5}+2}=\sqrt{5}-2\). Therefore the sum is \(2\sqrt{5}\).

Step 3

Exam Tip

\(\frac{1}{\sqrt{5}+2}=\sqrt{5}-2\) है। इसलिए योग \(2\sqrt{5}\) है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(t=\sqrt{5}+2\) है, तो \(t+\frac{1}{t}\) का मान क्या है? / If \(t=\sqrt{5}+2\), what is the value of \(t+\frac{1}{t}\)?

Correct Answer: A. \(2\sqrt{5}\). Explanation: \(\frac{1}{\sqrt{5}+2}=\sqrt{5}-2\) है। इसलिए योग \(2\sqrt{5}\) है। / \(\frac{1}{\sqrt{5}+2}=\sqrt{5}-2\). Therefore the sum is \(2\sqrt{5}\).

Which concept should I revise for this Mathematics MCQ?

\(\frac{1}{\sqrt{5}+2}=\sqrt{5}-2\). Therefore the sum is \(2\sqrt{5}\).

What exam hint can help solve this Mathematics question?

\(\frac{1}{\sqrt{5}+2}=\sqrt{5}-2\) है। इसलिए योग \(2\sqrt{5}\) है।