यदि \(t\neq0\), तो \(tx^{17}+0x^{19}+8x^{10}-7\) की डिग्री क्या है?
If \(t\neq0\), what is the degree of \(tx^{17}+0x^{19}+8x^{10}-7\)?
Explanation opens after your attempt
B. (17)
Concept
\(0x^{19}\) is a zero term, and \(t\neq0\) keeps the \(x^{17}\) term. Therefore the degree is (17).
Why this answer is correct
The correct answer is B. (17). \(0x^{19}\) is a zero term, and \(t\neq0\) keeps the \(x^{17}\) term. Therefore the degree is (17).
Exam Tip
\(0x^{19}\) शून्य पद है और \(t\neq0\) से \(x^{17}\) पद बचता है। इसलिए डिग्री (17) है।
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