यदि \(p=\sqrt{12}-\sqrt{3}\) है, तो \(p^2\) का मान क्या है?

If \(p=\sqrt{12}-\sqrt{3}\), what is the value of \(p^2\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. (3)

Step 1

Concept

\(\sqrt{12}=2\sqrt{3}\), so \(p=\sqrt{3}\). Therefore \(p^2=3\).

Step 2

Why this answer is correct

The correct answer is A. (3). \(\sqrt{12}=2\sqrt{3}\), so \(p=\sqrt{3}\). Therefore \(p^2=3\).

Step 3

Exam Tip

\(\sqrt{12}=2\sqrt{3}\), इसलिए \(p=\sqrt{3}\) है। अतः \(p^2=3\) होगा।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(p=\sqrt{12}-\sqrt{3}\) है, तो \(p^2\) का मान क्या है? / If \(p=\sqrt{12}-\sqrt{3}\), what is the value of \(p^2\)?

Correct Answer: A. (3). Explanation: \(\sqrt{12}=2\sqrt{3}\), इसलिए \(p=\sqrt{3}\) है। अतः \(p^2=3\) होगा। / \(\sqrt{12}=2\sqrt{3}\), so \(p=\sqrt{3}\). Therefore \(p^2=3\).

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{12}=2\sqrt{3}\), so \(p=\sqrt{3}\). Therefore \(p^2=3\).

What exam hint can help solve this Mathematics question?

\(\sqrt{12}=2\sqrt{3}\), इसलिए \(p=\sqrt{3}\) है। अतः \(p^2=3\) होगा।