यदि (p), (p+10), (3p-2) समांतर श्रेणी के लगातार तीन पद हैं, तो (p) क्या है?
If (p), (p+10), (3p-2) are three consecutive terms of an arithmetic progression, what is (p)?
Explanation opens after your attempt
C. (11)
Concept
From (2(p+10)=p+(3p-2)), (2p+20=4p-2), so (p=11). The middle term is the average of the two surrounding terms.
Why this answer is correct
The correct answer is C. (11). From (2(p+10)=p+(3p-2)), (2p+20=4p-2), so (p=11). The middle term is the average of the two surrounding terms.
Exam Tip
(2(p+10)=p+(3p-2)) से (2p+20=4p-2) और (p=11) मिलता है। बीच का पद दोनों ओर के पदों का औसत होता है।
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