यदि (p), (p+10), (3p-2) समांतर श्रेणी के लगातार तीन पद हैं, तो (p) क्या है?

If (p), (p+10), (3p-2) are three consecutive terms of an arithmetic progression, what is (p)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

C. (11)

Step 1

Concept

From (2(p+10)=p+(3p-2)), (2p+20=4p-2), so (p=11). The middle term is the average of the two surrounding terms.

Step 2

Why this answer is correct

The correct answer is C. (11). From (2(p+10)=p+(3p-2)), (2p+20=4p-2), so (p=11). The middle term is the average of the two surrounding terms.

Step 3

Exam Tip

(2(p+10)=p+(3p-2)) से (2p+20=4p-2) और (p=11) मिलता है। बीच का पद दोनों ओर के पदों का औसत होता है।

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Mathematics Answer, Explanation and Revision Hints

यदि (p), (p+10), (3p-2) समांतर श्रेणी के लगातार तीन पद हैं, तो (p) क्या है? / If (p), (p+10), (3p-2) are three consecutive terms of an arithmetic progression, what is (p)?

Correct Answer: C. (11). Explanation: (2(p+10)=p+(3p-2)) से (2p+20=4p-2) और (p=11) मिलता है। बीच का पद दोनों ओर के पदों का औसत होता है। / From (2(p+10)=p+(3p-2)), (2p+20=4p-2), so (p=11). The middle term is the average of the two surrounding terms.

Which concept should I revise for this Mathematics MCQ?

From (2(p+10)=p+(3p-2)), (2p+20=4p-2), so (p=11). The middle term is the average of the two surrounding terms.

What exam hint can help solve this Mathematics question?

(2(p+10)=p+(3p-2)) से (2p+20=4p-2) और (p=11) मिलता है। बीच का पद दोनों ओर के पदों का औसत होता है।