यदि (OA=1), (AB=1), (BC=1), और प्रत्येक नया खंड पिछले कर्ण पर लंब है, तो (OC) का वर्ग क्या होगा?

If (OA=1), (AB=1), (BC=1), and each new segment is perpendicular to the previous hypotenuse, what is the square of (OC)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. (3)

Step 1

Concept

First \(OB^2=2\), then \(OC^2=2+1=3\). The question asks for the square, so the answer is (3).

Step 2

Why this answer is correct

The correct answer is B. (3). First \(OB^2=2\), then \(OC^2=2+1=3\). The question asks for the square, so the answer is (3).

Step 3

Exam Tip

पहले \(OB^2=2\), फिर \(OC^2=2+1=3\)। प्रश्न वर्ग पूछता है, इसलिए उत्तर (3) है।

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यदि (OA=1), (AB=1), (BC=1), और प्रत्येक नया खंड पिछले कर्ण पर लंब है, तो (OC) का वर्ग क्या होगा? / If (OA=1), (AB=1), (BC=1), and each new segment is perpendicular to the previous hypotenuse, what is the square of (OC)?

Correct Answer: B. (3). Explanation: पहले \(OB^2=2\), फिर \(OC^2=2+1=3\)। प्रश्न वर्ग पूछता है, इसलिए उत्तर (3) है। / First \(OB^2=2\), then \(OC^2=2+1=3\). The question asks for the square, so the answer is (3).

Which concept should I revise for this Mathematics MCQ?

First \(OB^2=2\), then \(OC^2=2+1=3\). The question asks for the square, so the answer is (3).

What exam hint can help solve this Mathematics question?

पहले \(OB^2=2\), फिर \(OC^2=2+1=3\)। प्रश्न वर्ग पूछता है, इसलिए उत्तर (3) है।