यदि (OA=1), (AB=1), (BC=1), और प्रत्येक नया खंड पिछले कर्ण पर लंब है, तो (OC) का वर्ग क्या होगा?
If (OA=1), (AB=1), (BC=1), and each new segment is perpendicular to the previous hypotenuse, what is the square of (OC)?
Explanation opens after your attempt
B. (3)
Concept
First \(OB^2=2\), then \(OC^2=2+1=3\). The question asks for the square, so the answer is (3).
Why this answer is correct
The correct answer is B. (3). First \(OB^2=2\), then \(OC^2=2+1=3\). The question asks for the square, so the answer is (3).
Exam Tip
पहले \(OB^2=2\), फिर \(OC^2=2+1=3\)। प्रश्न वर्ग पूछता है, इसलिए उत्तर (3) है।
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