यदि \( \frac{p}{q} \) सरल रूप में है और \(q=2^8\), तो सांत दशमलव में अधिकतम कितने दशमलव स्थान होंगे?

If \( \frac{p}{q} \) is in simplest form and \(q=2^8\), what is the maximum number of decimal places in the terminating decimal?

Author: Muft Shiksha Editorial Team Published: Updated:
Explanation opens after your attempt
Correct Answer

C. (8)

Step 1

Concept

To make \(2^8\) into \(10^8\), we multiply by \(5^8\). So there will be at most (8) decimal places.

Step 2

Why this answer is correct

The correct answer is C. (8). To make \(2^8\) into \(10^8\), we multiply by \(5^8\). So there will be at most (8) decimal places.

Step 3

Exam Tip

\(2^8\) को \(10^8\) बनाने के लिए \(5^8\) से गुणा करना पड़ेगा। इसलिए अधिकतम (8) दशमलव स्थान होंगे।

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Mathematics Answer, Explanation and Revision Hints

यदि \( \frac{p}{q} \) सरल रूप में है और \(q=2^8\), तो सांत दशमलव में अधिकतम कितने दशमलव स्थान होंगे? / If \( \frac{p}{q} \) is in simplest form and \(q=2^8\), what is the maximum number of decimal places in the terminating decimal?

Correct Answer: C. (8). Explanation: \(2^8\) को \(10^8\) बनाने के लिए \(5^8\) से गुणा करना पड़ेगा। इसलिए अधिकतम (8) दशमलव स्थान होंगे। / To make \(2^8\) into \(10^8\), we multiply by \(5^8\). So there will be at most (8) decimal places.

Which concept should I revise for this Mathematics MCQ?

To make \(2^8\) into \(10^8\), we multiply by \(5^8\). So there will be at most (8) decimal places.

What exam hint can help solve this Mathematics question?

\(2^8\) को \(10^8\) बनाने के लिए \(5^8\) से गुणा करना पड़ेगा। इसलिए अधिकतम (8) दशमलव स्थान होंगे।