यदि किसी चरण में पिछली त्रिज्या \(\sqrt{8}\) है, तो अगली त्रिज्या की लंबाई क्या होगी?
If at a certain step the previous radius is \(\sqrt{8}\), what will be the length of the next radius?
Explanation opens after your attempt
A. \(\sqrt{9}\)
Concept
The square of the new radius is (8+1=9), so the length is \(\sqrt{9}\). Remember that the length is written as \(\sqrt{9}\), not just (9).
Why this answer is correct
The correct answer is A. \(\sqrt{9}\). The square of the new radius is (8+1=9), so the length is \(\sqrt{9}\). Remember that the length is written as \(\sqrt{9}\), not just (9).
Exam Tip
नई त्रिज्या का वर्ग (8+1=9) होगा, इसलिए लंबाई \(\sqrt{9}\) है। ध्यान रखें कि लंबाई (9) नहीं बल्कि \(\sqrt{9}\) लिखी जाती है।
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