वर्गमूल सर्पिल में यदि कोई विद्यार्थी \(\sqrt{n}+1=\sqrt{n+1}\) लिखकर अगला कर्ण बताता है, तो सुधार क्या होगा?
If a student writes \(\sqrt{n}+1=\sqrt{n+1}\) to state the next hypotenuse in a square root spiral, what is the correction?
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Correct Answer
A. सही रूप (\sqrt{\(\sqrt{n}\)2+12}=\sqrt{n+1}) हैThe correct form is (\sqrt{\(\sqrt{n}\)2+12}=\sqrt{n+1})
Concept
In a square root spiral, the hypotenuse is formed by Pythagoras theorem. Directly adding lengths is wrong.
Why this answer is correct
The correct answer is A. सही रूप (\sqrt{\(\sqrt{n}\)2+12}=\sqrt{n+1}) है / The correct form is (\sqrt{\(\sqrt{n}\)2+12}=\sqrt{n+1}). In a square root spiral, the hypotenuse is formed by Pythagoras theorem. Directly adding lengths is wrong.
Exam Tip
वर्गमूल सर्पिल में कर्ण पाइथागोरस से बनता है। सीधे लंबाइयों को जोड़ना गलत है।
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