यदि \(a_n=pn+q\), \(a_5=31\) और \(a_{12}=80\) है तो \(a_1\) क्या होगा?
If \(a_n=pn+q\), \(a_5=31\) and \(a_{12}=80\), what will \(a_1\) be?
Explanation opens after your attempt
C. (3)
Concept
\(p=\frac{80-31}{12-5}=7\) and (q=-4). Therefore \(a_1=7-4=3\).
Why this answer is correct
The correct answer is C. (3). \(p=\frac{80-31}{12-5}=7\) and (q=-4). Therefore \(a_1=7-4=3\).
Exam Tip
\(p=\frac{80-31}{12-5}=7\) और (q=-4) है। इसलिए \(a_1=7-4=3\) है।
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