If (a_n=n^2+5n), for which (n) will (a_n=126)?
Answer and explanation
Correct answer: 9
Given \(n^2+5n=126\), we get \(n^2+5n-126=0\). Factoring gives \((n-9)(n+14)=0\), so \(n=9\) or \(n=-14\). Since a term position \(n\) in a sequence is positive, \(n=9\) is correct. For example, \(n=8\) gives 104, not 126. Exam tip: bring all terms to one side and factor the quadratic expression.
Frequently asked questions
What is the correct answer to this question?
9
Why is this the correct answer?
Given \(n^2+5n=126\), we get \(n^2+5n-126=0\). Factoring gives \((n-9)(n+14)=0\), so \(n=9\) or \(n=-14\). Since a term position \(n\) in a sequence is positive, \(n=9\) is correct. For example, \(n=8\) gives 104, not 126. Exam tip: bring all terms to one side and factor the quadratic expression.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Explicit or general rule.
Student feedback
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
