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If \(a_n=\frac{n(2n+3)}{2}\), what is the value of \(a_6\)?

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Answer and explanation

Correct answer: 45

Given \(a_n=\frac{n(2n+3)}{2}\). Substituting \(n=6\), \(a_6=\frac{6(2\times6+3)}{2}=\frac{6\times15}{2}=45\). Hence, 45 is correct. An answer such as 42 may result from evaluating \(2n+3\) incorrectly or making an error in multiplication or division. Exam tip: substitute the value of \(n\) first, then simplify the bracket and calculate step by step.

Related tags

SequencesProgressionsExplicit FormulaSubstitutionAlgebraClass 9

Frequently asked questions

What is the correct answer to this question?

45

Why is this the correct answer?

Given \(a_n=\frac{n(2n+3)}{2}\). Substituting \(n=6\), \(a_6=\frac{6(2\times6+3)}{2}=\frac{6\times15}{2}=45\). Hence, 45 is correct. An answer such as 42 may result from evaluating \(2n+3\) incorrectly or making an error in multiplication or division. Exam tip: substitute the value of \(n\) first, then simplify the bracket and calculate step by step.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Explicit or general rule.

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