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If (a_n=3n^2+4), what is the value of (a_2+a_5)?
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Answer and explanation
Correct answer: \(95\)
Given \(a_n=3n^2+4\), \(a_2=3(2)^2+4=16\) and \(a_5=3(5)^2+4=79\). Therefore, \(a_2+a_5=16+79=95\). A value such as \(93\) usually results from an error while squaring or adding a term. Exam tip: evaluate each required term separately before adding them.
Frequently asked questions
What is the correct answer to this question?
\(95\)
Why is this the correct answer?
Given \(a_n=3n^2+4\), \(a_2=3(2)^2+4=16\) and \(a_5=3(5)^2+4=79\). Therefore, \(a_2+a_5=16+79=95\). A value such as \(93\) usually results from an error while squaring or adding a term. Exam tip: evaluate each required term separately before adding them.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Explicit or general rule.
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