यदि \(a_n=128\left(\frac{1}{2}\right)^{n-1}\) है, तो कौन-सा पद (8) के बराबर होगा?
If \(a_n=128\left(\frac{1}{2}\right)^{n-1}\), which term will be equal to (8)?
Explanation opens after your attempt
Correct Answer
B. पाँचवाँ पद(5)th term
Concept
From \(128\left(\frac{1}{2}\right)^{n-1}=8\), \(\left(\frac{1}{2}\right)^{n-1}=\frac{1}{16}\), so (n=5). In exams, simplify fractions first.
Why this answer is correct
The correct answer is B. पाँचवाँ पद / (5)th term. From \(128\left(\frac{1}{2}\right)^{n-1}=8\), \(\left(\frac{1}{2}\right)^{n-1}=\frac{1}{16}\), so (n=5). In exams, simplify fractions first.
Exam Tip
\(128\left(\frac{1}{2}\right)^{n-1}=8\) से \(\left(\frac{1}{2}\right)^{n-1}=\frac{1}{16}\), इसलिए (n=5) है। परीक्षा में भिन्नों को पहले सरल करें।
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