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If a model of a square with side (g-1) is made, what will be the total area?

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Answer and explanation

Correct answer: \(g^2-2g+1\)

The area of a square equals the square of its side. Therefore, for side \((g-1)\), the area is \((g-1)^2\). Applying \((a-b)^2=a^2-2ab+b^2\) with \(a=g\) and \(b=1\) gives \(g^2-2g+1\). The expression \(g^2-1\) is a difference of squares, not the square of a difference. Exam tip: the middle term in \((a-b)^2\) is always \(-2ab\).

Related tags

Algebraic IdentitiesSquare Of DifferenceArea ModelVisual AlgebraPolynomial Expansion

Frequently asked questions

What is the correct answer to this question?

\(g^2-2g+1\)

Why is this the correct answer?

The area of a square equals the square of its side. Therefore, for side \((g-1)\), the area is \((g-1)^2\). Applying \((a-b)^2=a^2-2ab+b^2\) with \(a=g\) and \(b=1\) gives \(g^2-2g+1\). The expression \(g^2-1\) is a difference of squares, not the square of a difference. Exam tip: the middle term in \((a-b)^2\) is always \(-2ab\).

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Exploring Algebraic Identities. Topic: Visual models of identities.

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