यदि \(a=7+\sqrt{2}\) और \(b=7-\sqrt{2}\) हैं तो \(a^2-b^2\) का मान क्या है?
If \(a=7+\sqrt{2}\) and \(b=7-\sqrt{2}\), what is the value of \(a^2-b^2\)?
Explanation opens after your attempt
Correct Answer
B. \(28\sqrt{2}\)
Concept
\(a-b=2\sqrt{2}\) and (a+b=14). Therefore \(a^2-b^2=28\sqrt{2}\).
Why this answer is correct
The correct answer is B. \(28\sqrt{2}\). \(a-b=2\sqrt{2}\) and (a+b=14). Therefore \(a^2-b^2=28\sqrt{2}\).
Exam Tip
\(a-b=2\sqrt{2}\) और (a+b=14) है। इसलिए \(a^2-b^2=28\sqrt{2}\) है।
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