यदि \(a=6+\sqrt{5}\) और \(b=6-\sqrt{5}\) हैं तो \(a^2-b^2\) का मान क्या है?
If \(a=6+\sqrt{5}\) and \(b=6-\sqrt{5}\), what is the value of \(a^2-b^2\)?
Explanation opens after your attempt
Correct Answer
A. \(24\sqrt{5}\)
Concept
(a-2-b-2=(a-b)(a+b)) where \(a-b=2\sqrt{5}\) and (a+b=12). So the value is \(24\sqrt{5}\).
Why this answer is correct
The correct answer is A. \(24\sqrt{5}\). (a-2-b-2=(a-b)(a+b)) where \(a-b=2\sqrt{5}\) and (a+b=12). So the value is \(24\sqrt{5}\).
Exam Tip
(a-2-b-2=(a-b)(a+b)) है जहाँ \(a-b=2\sqrt{5}\) और (a+b=12) है। इसलिए मान \(24\sqrt{5}\) है।
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