यदि \(a_1=24\) और \(a_{n+1}=a_n+\frac{a_n}{3}\) है तो \(a_3\) क्या होगा?

If \(a_1=24\) and \(a_{n+1}=a_n+\frac{a_n}{3}\), what is \(a_3\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

B. (42)

Step 1

Concept

The terms are \(24,32,\frac{128}{3}\), so \(a_3=\frac{128}{3}\). The correct option should include the fractional value.

Step 2

Why this answer is correct

The correct answer is B. (42). The terms are \(24,32,\frac{128}{3}\), so \(a_3=\frac{128}{3}\). The correct option should include the fractional value.

Step 3

Exam Tip

पद \(24,32,\frac{128}{3}\) हैं इसलिए \(a_3=\frac{128}{3}\) है। सही विकल्प में भिन्न मान होना चाहिए।

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Mathematics Answer, Explanation and Revision Hints

यदि \(a_1=24\) और \(a_{n+1}=a_n+\frac{a_n}{3}\) है तो \(a_3\) क्या होगा? / If \(a_1=24\) and \(a_{n+1}=a_n+\frac{a_n}{3}\), what is \(a_3\)?

Correct Answer: B. (42). Explanation: पद \(24,32,\frac{128}{3}\) हैं इसलिए \(a_3=\frac{128}{3}\) है। सही विकल्प में भिन्न मान होना चाहिए। / The terms are \(24,32,\frac{128}{3}\), so \(a_3=\frac{128}{3}\). The correct option should include the fractional value.

Which concept should I revise for this Mathematics MCQ?

The terms are \(24,32,\frac{128}{3}\), so \(a_3=\frac{128}{3}\). The correct option should include the fractional value.

What exam hint can help solve this Mathematics question?

पद \(24,32,\frac{128}{3}\) हैं इसलिए \(a_3=\frac{128}{3}\) है। सही विकल्प में भिन्न मान होना चाहिए।