यदि \(a_1=2\), \(a_2=5\) और \(a_n=a_{n-1}+2a_{n-2}\) है तो \(a_5\) क्या होगा?

If \(a_1=2\), \(a_2=5\), and \(a_n=a_{n-1}+2a_{n-2}\), what is \(a_5\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. (27)

Step 1

Concept

The terms give \(a_3=9\), \(a_4=19\), and \(a_5=37\). Exam tip: multiply \(a_{n-2}\) by (2) before adding.

Step 2

Why this answer is correct

The correct answer is B. (27). The terms give \(a_3=9\), \(a_4=19\), and \(a_5=37\). Exam tip: multiply \(a_{n-2}\) by (2) before adding.

Step 3

Exam Tip

पद (2,5,9,19,37) नहीं हैं क्योंकि \(a_5=19+2\times9=37\) होगा। इसलिए सही मान (37) है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(a_1=2\), \(a_2=5\) और \(a_n=a_{n-1}+2a_{n-2}\) है तो \(a_5\) क्या होगा? / If \(a_1=2\), \(a_2=5\), and \(a_n=a_{n-1}+2a_{n-2}\), what is \(a_5\)?

Correct Answer: B. (27). Explanation: पद (2,5,9,19,37) नहीं हैं क्योंकि \(a_5=19+2\times9=37\) होगा। इसलिए सही मान (37) है। / The terms give \(a_3=9\), \(a_4=19\), and \(a_5=37\). Exam tip: multiply \(a_{n-2}\) by (2) before adding.

Which concept should I revise for this Mathematics MCQ?

The terms give \(a_3=9\), \(a_4=19\), and \(a_5=37\). Exam tip: multiply \(a_{n-2}\) by (2) before adding.

What exam hint can help solve this Mathematics question?

पद (2,5,9,19,37) नहीं हैं क्योंकि \(a_5=19+2\times9=37\) होगा। इसलिए सही मान (37) है।