यदि \(a_1=150\) और (a_{n+1}=a_n-\(n^2+n\)) है तो कौन सा पद (110) है?

If \(a_1=150\) and (a_{n+1}=a_n-\(n^2+n\)), which term is (110)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. (5)वाँ(5)th

Step 1

Concept

The terms are (150,148,142,130,110), so (110) is the fifth term. Exam tip: write decreasing terms with positions.

Step 2

Why this answer is correct

The correct answer is B. (5)वाँ / (5)th. The terms are (150,148,142,130,110), so (110) is the fifth term. Exam tip: write decreasing terms with positions.

Step 3

Exam Tip

पद (150,148,142,130,110) हैं इसलिए (110) पाँचवाँ पद है। घटते हुए पदों को क्रमांक सहित लिखें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(a_1=150\) और (a_{n+1}=a_n-\(n^2+n\)) है तो कौन सा पद (110) है? / If \(a_1=150\) and (a_{n+1}=a_n-\(n^2+n\)), which term is (110)?

Correct Answer: B. (5)वाँ / (5)th. Explanation: पद (150,148,142,130,110) हैं इसलिए (110) पाँचवाँ पद है। घटते हुए पदों को क्रमांक सहित लिखें। / The terms are (150,148,142,130,110), so (110) is the fifth term. Exam tip: write decreasing terms with positions.

Which concept should I revise for this Mathematics MCQ?

The terms are (150,148,142,130,110), so (110) is the fifth term. Exam tip: write decreasing terms with positions.

What exam hint can help solve this Mathematics question?

पद (150,148,142,130,110) हैं इसलिए (110) पाँचवाँ पद है। घटते हुए पदों को क्रमांक सहित लिखें।