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How many terms remain after simplifying (7p^2q-2pq+5pq-4p^2q+9)?(7p^2q-2pq+5pq-4p^2q+9) को सरल करने पर कितने पद रहेंगे?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 33
Combine like terms: \(7p^2q-4p^2q=3p^2q\) and \(-2pq+5pq=3pq\). Thus, the expression becomes \(3p^2q+3pq+9\), which has three terms: \(3p^2q\), \(3pq\), and \(9\). Note that \(p^2q\) and \(pq\) are not like terms because the exponent of \(p\) is different. Exam tip: combine only terms with identical variables and exponents.समान पदों को मिलाएँ: \(7p^2q-4p^2q=3p^2q\) और \(-2pq+5pq=3pq\)। अतः व्यंजक \(3p^2q+3pq+9\) बनता है, जिसमें \(3p^2q\), \(3pq\) और \(9\)—कुल 3 पद हैं। \(p^2q\) और \(pq\) समान पद नहीं हैं, क्योंकि \(p\) की घात अलग-अलग है। परीक्षा टिप: केवल उन्हीं पदों को जोड़ें या घटाएँ जिनके चर और उनकी घातें समान हों।
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