गुणोत्तर श्रेणी \(3,12,48,\ldots\) में (12288) तक कितने पद हैं?
How many terms are there up to (12288) in the geometric progression \(3,12,48,\ldots\)?
Explanation opens after your attempt
Correct Answer
B. (7)
Concept
\(3\cdot4^{n-1}=12288\), so \(4^{n-1}=4096=4^6\) and (n=7). In exams, equate the last term to the general term.
Why this answer is correct
The correct answer is B. (7). \(3\cdot4^{n-1}=12288\), so \(4^{n-1}=4096=4^6\) and (n=7). In exams, equate the last term to the general term.
Exam Tip
\(3\cdot4^{n-1}=12288\) से \(4^{n-1}=4096=4^6\), इसलिए (n=7) है। परीक्षा में अंतिम पद को सामान्य पद के बराबर रखें।
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