किस मान पर (\(t^2-9\)x+(t-3)) रेखीय बहुपद नहीं रहेगा?

For which value will (\(t^2-9\)x+(t-3)) not remain a linear polynomial?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. (t=3) या (t=-3)(t=3) or (t=-3)

Step 1

Concept

For it to be linear, \(t^2-9\neq0\) is needed. At \(t=\pm3\), the coefficient of (x) becomes (0).

Step 2

Why this answer is correct

The correct answer is A. (t=3) या (t=-3) / (t=3) or (t=-3). For it to be linear, \(t^2-9\neq0\) is needed. At \(t=\pm3\), the coefficient of (x) becomes (0).

Step 3

Exam Tip

रेखीय होने के लिए \(t^2-9\neq0\) चाहिए। \(t=\pm3\) पर (x) का गुणांक (0) हो जाता है।

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Mathematics Answer, Explanation and Revision Hints

किस मान पर (\(t^2-9\)x+(t-3)) रेखीय बहुपद नहीं रहेगा? / For which value will (\(t^2-9\)x+(t-3)) not remain a linear polynomial?

Correct Answer: A. (t=3) या (t=-3) / (t=3) or (t=-3). Explanation: रेखीय होने के लिए \(t^2-9\neq0\) चाहिए। \(t=\pm3\) पर (x) का गुणांक (0) हो जाता है। / For it to be linear, \(t^2-9\neq0\) is needed. At \(t=\pm3\), the coefficient of (x) becomes (0).

Which concept should I revise for this Mathematics MCQ?

For it to be linear, \(t^2-9\neq0\) is needed. At \(t=\pm3\), the coefficient of (x) becomes (0).

What exam hint can help solve this Mathematics question?

रेखीय होने के लिए \(t^2-9\neq0\) चाहिए। \(t=\pm3\) पर (x) का गुणांक (0) हो जाता है।