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In a square of side (q+8), what is the area of each of the two equal rectangles?

Answer and explanation

Correct answer: 8q

The correct answer is A: 8q. Divide each side of the square, q+8, into parts q and 8. In the area model, one crosswise rectangle has dimensions q and 8. Its area is q×8=8q. The second equal rectangle has the same dimensions in the opposite direction, so it also has area 8q. Option A is correct because the question asks for the area of each individual rectangle, not the combined area of both; together they would contribute 16q. Option B, 16q, is the total area of the two equal rectangles, so it is not the area of one rectangle. Option C, 64, is the area of the small 8-by-8 square. Option D, q², is the area of the q-by-q square. The complete square expansion is (q+8)²=q²+16q+64. Memory cue: one ab rectangle has area ab, while two equal rectangles together have area 2ab.

Related tags

Equal RectanglesArea ModelBinomial SquareVisual ModelsVisual Models Of IdentitiesExploring Algebraic IdentitiesMathematicsClass 9 Mcq

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