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A visual model shows three areas: (x+y)², (x−y)², and 4xy. Which relation is correct?

Answer and explanation

Correct answer: (x+y)² = (x−y)² + 4xy

The direct answer is option A. Expand both square expressions or subtract them carefully: (x+y)² = x² + 2xy + y², while (x−y)² = x² − 2xy + y². Subtracting the second from the first gives [(x+y)² − (x−y)²] = 4xy. Rearranging yields (x+y)² = (x−y)² + 4xy. Thus the larger square-of-a-sum area consists of the square-of-a-difference area plus the additional 4xy area. Option B reverses the two square areas and would require 4xy to be negative in the usual positive-area setting. Option C adds the two squares; their sum is 2x² + 2y², not generally 4xy. Option D uses the wrong sign. A quick memory cue is: the difference between the square of a sum and the square of a difference is four times the product, so the plus-square equals the minus-square plus 4xy.

Related tags

Difference Of SquaresArea ComparisonVisual IdentityVisual Models Of IdentitiesExploring Algebraic IdentitiesMathematicsClass 9 Mcq

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