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If the sum of only the squares is removed from the area model of ((x+y+z)^2), what remains?

Answer and explanation

Correct answer: 2xy+2yz+2zx

The direct answer is A. Expand the square of three terms by viewing the model as nine regions: three square regions x^2, y^2, z^2 and six mixed rectangles. The expansion is (x+y+z)^2=x^2+y^2+z^2+2xy+2yz+2zx. If only the sum of the three square regions, x^2+y^2+z^2, is removed, the six mixed rectangles remain. The two rectangles involving x and y contribute 2xy; those involving y and z contribute 2yz; and those involving z and x contribute 2zx. Their total is 2xy+2yz+2zx. B forgets that every pair appears twice. C is the sum of side expressions, not an area. D has three variables multiplied together and is not produced by squaring a sum. Memory cue: in a three-term square, every pair contributes twice.

Related tags

Three-Term-SquareMixed-RectanglesArea-ExpansionVisual Models Of IdentitiesExploring Algebraic IdentitiesMathematicsClass 9 Mcq

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