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In a square of side a+b, if the widths of the a strip and b strip are interchanged but the total side remains the same, which area relation remains unchanged?

Answer and explanation

Correct answer: (a+b)² = a² + 2ab + b²

The direct answer is A: (a+b)² = a² + 2ab + b². A square with side a+b can be divided into one a-by-a square, one b-by-b square, and two rectangles, each with area ab. Their total area is a² + ab + ab + b² = a² + 2ab + b². If the a and b strips are interchanged, the pieces may move or change position, but their dimensions and total area do not change. Therefore the same identity remains true. Option B is a different identity involving the difference a−b; it is not the area of the stated square. Option C is false because a²−b² is (a−b)(a+b), not generally (a−b)². Option D forgets the two rectangular areas 2ab. Memory cue: rearranging pieces preserves total area, and the two cross-rectangles create the middle term 2ab.

Related tags

Area ModelBinomial SquareRearrangementAlgebraic IdentityVisual Models Of IdentitiesExploring Algebraic IdentitiesMathematicsClass 9 Mcq

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