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A large square model contains (a^2+b^2+c^2+2ab+2ac+2bc). If all strips involving (c) and the (c^2) corner are removed, what area remains?

Answer and explanation

Correct answer: a^2+b^2+2ab / square of (a+b)

The correct answer is A: a^2+b^2+2ab. The complete expression is (a+b+c)^2. Its pieces are three corner squares a^2, b^2, c^2 and three pairs of strips: 2ab, 2ac and 2bc. If every part involving c is removed, remove c^2, 2ac and 2bc. The remaining pieces are a^2+b^2+2ab. These pieces form the square identity (a+b)^2, because a^2+2ab+b^2=(a+b)^2. Option A includes exactly all parts made from a and b. Option B incorrectly keeps c^2 even though the c corner is removed and also omits the ab strips. Option C lists the removed c-related area rather than the area left behind. Option D includes only one of the two ab rectangles, so it is incomplete. Memory cue: after removing all c-parts, simply set c=0 in (a+b+c)^2; the result is (a+b)^2.

Related tags

Three-Part SquareRemoval ModelArea PartitionPerfect SquareVisual Models Of IdentitiesExploring Algebraic IdentitiesMathematicsClass 9 Mcq

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