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In the visual model of a square with side 3a+2b, what will be the combined area of the two equal rectangles?

Answer and explanation

Correct answer: 12ab

The correct answer is D. Split each side of the square into lengths 3a and 2b. The two equal off-diagonal rectangles each have dimensions 3a by 2b, so each has area (3a)(2b)=6ab. Since there are two such rectangles, their combined area is 6ab+6ab=12ab. This is also the middle term in (3a+2b)^2=(3a)^2+2(3a)(2b)+(2b)^2=9a^2+12ab+4b^2. A is the area of only one rectangle, not both. B is merely the sum of the numerical side coefficients and has no correct area dimensions. C adds the two square areas but leaves out the rectangles. Memory cue: the two middle regions in (u+v)^2 together equal 2uv.

Related tags

Binomial-SquareArea-ModelMiddle-TermVisual-IdentityVisual Models Of IdentitiesExploring Algebraic IdentitiesMathematicsClass 9 Mcq

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