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In a visual proof, the same large square area is written as (a+b)^2 and (a^2+2ab+b^2). What is the conclusion?

Answer and explanation

Correct answer: Both areas are equal

The direct answer is A: both areas are equal. A visual proof works by calculating the area of one unchanged figure in two different ways. The large square has side a+b, so its area is (a+b)^2. If the same square is divided into one a-by-a square, two a-by-b rectangles, and one b-by-b square, the parts have areas a², ab, ab, and b². Their sum is a²+ab+ab+b²=a²+2ab+b². Because both calculations describe the same complete square, the expressions must be equal. B is false because neither expression is generally larger. C is false because the second expression is an area, not always zero. D is false because the figure is the same, only the partition or calculation differs. Memory cue: same figure plus two valid area calculations gives an identity.

Related tags

Visual-ProofArea-IdentityAlgebraic-IdentityVisual Models Of IdentitiesExploring Algebraic IdentitiesMathematicsClass 9 Mcq

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