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Which arrangement of regions must appear in an area model of the identity \((a+b)^2=a^2+2ab+b^2\)?

Answer and explanation

Correct answer: One \(a^2\) square, one \(b^2\) square, and two \(ab\) rectangles

Answer: A. Imagine a large square whose side is split into lengths \(a\) and \(b\) in both directions. The \(a\)-by-\(a\) corner is a square of area \(a^2\), and the \(b\)-by-\(b\) corner is a square of area \(b^2\). The remaining two corners each have side lengths \(a\) and \(b\), so each is an \(ab\) rectangle. Their combined area is \(ab+ab=2ab\). Adding every region gives \(a^2+2ab+b^2=(a+b)^2\). B misses one cross rectangle and therefore gives only \(a^2+ab+b^2\). C has the wrong number of \(a^2\) squares. D uses incorrect shapes and areas. Memory cue: a binomial square has two end squares and two identical cross rectangles.

Related tags

Visual Models Of IdentitiesExploring Algebraic IdentitiesMathematicsClass 9 Mcq

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