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How many rectangular ab parts are there in a square of side a+b?

Answer and explanation

Correct answer: 2

The direct answer is C: two. Divide the side a+b into segments a and b in both directions. This partitions the large square into four regions: one a-by-a square with area a^2, two cross-rectangles with dimensions a and b and area ab each, and one b-by-b square with area b^2. Therefore the full area is (a+b)^2=a^2+ab+ab+b^2=a^2+2ab+b^2. The coefficient 2 in 2ab is not accidental; it counts the two rectangular ab parts. A counts only one cross-rectangle and misses the other. B counts three, but the third region is a square, not an ab rectangle. C is correct because exactly two regions have side lengths a and b. D incorrectly treats all four regions as ab rectangles, although two are squares. Memory cue: the middle term 2ab means two identical cross-rectangles in the plus-square diagram.

Related tags

Area PartsAb RectanglesSquare ModelVisual Models Of IdentitiesExploring Algebraic IdentitiesMathematicsClass 9 Mcq

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