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If 99² is found using the model of (100−1)², what is the correct value?

Answer and explanation

Correct answer: 9801

The direct answer is A, 9801. Begin with the difference-of-two-terms square identity: (a−b)² = a² − 2ab + b². Here a = 100 and b = 1 because 99 = 100−1. First calculate a² = 100² = 10,000. Next calculate the middle term 2ab = 2×100×1 = 200. Finally b² = 1² = 1. Substitution gives (100−1)² = 10,000 − 200 + 1 = 9,801. Option A is therefore correct. Option B, 9901, subtracts only 100 or otherwise mishandles the middle term; the correct middle term is 200. Option C, 9999, is close to 10,000 but does not apply the square identity correctly. Option D, 10001, is greater than 10,000, whereas squaring 99 must give a number slightly less than 100². A quick check is 99×99 = 9801. Memory cue: for a number one less than 100, subtract 200 and add 1.

Related tags

Algebraic IdentitiesPerfect SquaresNear HundredVisual ModelsVisual Models Of IdentitiesExploring Algebraic IdentitiesMathematicsClass 9 Mcq

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