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Which is the factorised form of (8x^3+27y^3)?

Answer and explanation

Correct answer: \((2x+3y)(4x^2-6xy+9y^2)\)

The expression is \(8x^3+27y^3=(2x)^3+(3y)^3\). Applying the sum-of-cubes identity \(a^3+b^3=(a+b)(a^2-ab+b^2)\) gives \((2x+3y)(4x^2-6xy+9y^2)\). Hence, option A is correct. Option B is associated with the difference-of-cubes identity \(a^3-b^3\), so it does not apply here. Exam tip: in a sum of cubes, the middle term of the second factor is negative.

Related tags

FactorisationSum Of CubesAlgebraic IdentitiesPerfect CubesClass 9 MathematicsExploring Algebraic IdentitiesMathematicsClass 9 Mcq

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