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Which answer is correct after factorising (2x^2+9x+10)?

Answer and explanation

Correct answer: ((2x+5)(x+2))

The direct answer is option A: \((2x+5)(x+2)\). For \(2x^2+9x+10\), multiply the first and last coefficients: \(2\times10=20\). We need two numbers with product 20 and sum 9; 4 and 5 work. Split the middle term: \(9x=4x+5x\). Then \(2x^2+4x+5x+10 = 2x(x+2)+5(x+2)\). Taking the common bracket gives \((2x+5)(x+2)\). Option A expands as \(2x^2+4x+5x+10=2x^2+9x+10\). Option B expands to \(2x^2+10x+2x+10=2x^2+12x+10\), so its middle coefficient is wrong. Option C gives \(x^2+9x+20\), with the leading and constant terms wrong. Option D gives \(2x^2+12x+10\), same incorrect middle coefficient as B. Always verify by multiplication. Memory cue: multiply the outside coefficients, split the middle term, then group.

Related tags

Quadratic FactorisationVerificationMiddle Term

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