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What is the factorised form of (x^2-3x-xy+3y)?

Answer and explanation

Correct answer: \((x-y)(x-3)\)

Grouping the terms gives \(x^2-3x-xy+3y=x(x-3)-y(x-3)\). Since \((x-3)\) is the common binomial factor, the expression is \((x-3)(x-y)\), or equivalently \((x-y)(x-3)\). Option B produces \(+xy\) on expansion, but the given expression has \(-xy\). Exam tip: in grouping, factor each pair first and then identify the common binomial factor.

Related tags

FactorisationGrouping MethodCommon FactorAlgebraic IdentitiesClass 9 MathematicsExploring Algebraic IdentitiesMathematicsClass 9 Mcq

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