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Factorise (x^3-6x^2+12x-8).(x^3-6x^2+12x-8) को गुणनखंडित करें।
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ((x-2)^3)सही पूर्ण घन
It is ((x-2)^3) because the expansion gives (x^3-6x^2+12x-8). In exams match the signs of a perfect cube in order.यह ((x-2)^3) है क्योंकि विस्तार (x^3-6x^2+12x-8) मिलता है। परीक्षा में पूर्ण घन के संकेतों को क्रम से मिलाएं।
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