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What is the factorised form of (4p^2-12pq+9q^2-25r^2)?

Answer and explanation

Correct answer: ( (2p-3q-5r)(2p-3q+5r) )

The direct answer is option D: (2p−3q−5r)(2p−3q+5r). First group the expression as (4p²−12pq+9q²)−25r². The first group is (2p−3q)² because its terms are (2p)²−2(2p)(3q)+(3q)². Also, 25r²=(5r)². Thus the whole expression is A²−B² with A=2p−3q and B=5r, so it factors as (A−B)(A+B), giving option D. Option A would use (2p+3q)² and would produce a positive 12pq, so its sign is wrong. Option B leaves the difference of squares partly unfactored, so it is not the complete factorised form requested. Option C does not expand to the original expression. D is exact. Memory cue: first complete the three-term square, then apply difference of squares.

Related tags

Perfect SquareDifference Of SquaresFactorisation

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