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Which expression has x − 2y as a factor in its complete factorisation?

Answer and explanation

Correct answer: x³ − 8y³

The correct answer is A: x³ − 8y³. Recognise 8y³ as (2y)³. Thus x³ − 8y³ = x³ − (2y)³. The difference-of-cubes identity is U³ − V³ = (U − V)(U² + UV + V²). Using U = x and V = 2y gives (x − 2y)(x² + 2xy + 4y²), so x − 2y is a factor. Option B is a sum of cubes and contains x + 2y, not x − 2y. Option C is not a difference of cubes. Option D is the second factor produced after factoring A, but it does not itself contain x − 2y as a factor over the usual polynomial factors. Memory cue: for a difference of cubes, the first factor keeps the same minus sign.

Related tags

Difference Of CubesFactorisationPolynomial FactorsAlgebraic IdentitiesExploring Algebraic IdentitiesMathematicsClass 9 Mcq

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