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What is the factorised form of a³ + 64?

Answer and explanation

Correct answer: (a + 4)(a² − 4a + 16)

The direct answer is A: (a + 4)(a² − 4a + 16). Since 64 = 4³, the expression is a³ + 4³, a sum of cubes. Use the identity u³ + v³ = (u + v)(u² − uv + v²). Taking u = a and v = 4 gives a³ + 4³ = (a + 4)(a² − 4a + 16). To verify, multiply: a(a² − 4a + 16) + 4(a² − 4a + 16) = a³ − 4a² + 16a + 4a² − 16a + 64 = a³ + 64. Option B is the difference-of-cubes pattern and would represent a³ − 64. Option C has the wrong signs in the second bracket; its expansion contains extra terms rather than cancelling them. Option D uses 8, but 8³ is 512, not 64, so it does not match the expression. Memory cue: for a sum of cubes, the signs are plus in the first bracket, then minus and plus in the second bracket.

Related tags

Sum Of CubesAlgebraic IdentityFactorisationExploring Algebraic IdentitiesMathematicsClass 9 Mcq

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