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In which form can \(x^2+4xy+4y^2\) be written?

Answer and explanation

Correct answer: \((x+2y)^2\)

The direct answer is C: \((x+2y)^2\). Compare the expression with the identity \((p+q)^2=p^2+2pq+q^2\). Take \(p=x\) and \(q=2y\). Then \(p^2=x^2\), \(2pq=2(x)(2y)=4xy\), and \(q^2=4y^2\). These are exactly the three terms given, so the expression is \((x+2y)^2\). A would expand to \(x^2+8xy+16y^2\), so its middle and last terms are too large. B gives \(x^2-4xy+4y^2\), with the wrong middle sign. D uses the difference-of-squares identity and gives \(x^2-4y^2\), which has no middle term. The quick check is that the middle term must be twice the product of the two quantities being squared.

Related tags

Perfect SquareAlgebraic IdentitiesTwo VariablesFactorisationExploring Algebraic IdentitiesMathematicsClass 9 Mcq

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