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What is the factorised form of s² − 12s + 36?

Answer and explanation

Correct answer: (s − 6)²

The direct answer is B: (s − 6)². Use the identity (a − b)² = a² − 2ab + b². In this expression, s² is the first square, 36 = 6² is the last square, and the middle term is −12s = −2 × s × 6. Therefore s² − 12s + 36 = (s − 6)². Expanding option B gives s² − 6s − 6s + 36 = s² − 12s + 36. Option A, (s + 6)², gives s² + 12s + 36, so its middle sign is wrong. Option C expands to s² − 9s − 36, which has both an incorrect middle coefficient and an incorrect constant sign. Option D expands to s² − 15s + 36, so its middle coefficient is wrong. The important cue is the sign of the middle term: a negative middle term in a perfect-square trinomial requires subtraction inside the bracket.

Related tags

Perfect Square TrinomialMinus IdentityFactorisationClass 9 MathematicsExploring Algebraic IdentitiesMathematicsClass 9 Mcq

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