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What are the factors of c² − 6c + 8?

Answer and explanation

Correct answer: (c − 2)(c − 4)

The direct answer is A: (c − 2)(c − 4). For a monic quadratic c² + bc + d, find two numbers whose product is d and whose sum is b. Here the constant term is 8 and the middle coefficient is −6. The numbers −2 and −4 have product (−2)(−4) = 8 and sum −2 + (−4) = −6. Hence c² − 6c + 8 = (c − 2)(c − 4). Expanding confirms it: c² − 4c − 2c + 8 = c² − 6c + 8. Option B has factors +2 and +4, producing c² + 6c + 8, so the middle sign is wrong. Option C has product 8 but sum −9, giving c² − 9c + 8. Option D has product −8, not +8, and gives c² − 2c − 8. The memory cue is: a positive constant with a negative middle term usually requires two negative factors.

Related tags

Signed TrinomialFactorisationQuadratic ExpressionsClass 9 MathematicsExploring Algebraic IdentitiesMathematicsClass 9 Mcq

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