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Which of the following expressions is in the form of a difference of two perfect squares, \(a^2-b^2\)?

Answer and explanation

Correct answer: \(9p^2 - 16q^2\)

Correct answer: A. The identity for a difference of two squares is \(a^2-b^2=(a-b)(a+b)\). In A, \(9p^2=(3p)^2\) and \(16q^2=(4q)^2\), and the sign between them is minus. Hence \(9p^2-16q^2=(3p)^2-(4q)^2\), exactly the required form; it can further factorise as \((3p-4q)(3p+4q)\). B contains a plus sign, so it is a sum of squares, not a difference. C and D contain three terms and include the mixed term \(24pq\); they are perfect-square trinomials, not two-square differences. In C, the identity is \((3p-4q)^2\), while D is \((3p+4q)^2\). Memory cue: difference of squares has exactly two square terms separated by a minus sign, and its factors have opposite signs.

Related tags

Algebraic IdentitiesFactorisationDifference Of SquaresPerfect SquaresClass 9 MathematicsExploring Algebraic IdentitiesMathematicsClass 9 Mcq

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