After taking out the common factor in \(7a^2-14a\), what remains?

Correct answer: \(a-2\)

Answer: A, \(a-2\). First identify the greatest common factor of the two terms \(7a^2\) and \(-14a\). Both contain 7a, so take \(7a\) outside. Divide the first term by it: \(7a^2\div7a=a\). Divide the second term by it: \(-14a\div7a=-2\). Thus, \(7a^2-14a=7a(a-2)\), and the part left inside the bracket is \(a-2\). Option A states exactly what remains. Option B is the complete factorised expression, not merely the bracketed remainder. Option C is wrong because the second term would need to be \(-14\), but division by \(7a\) gives \(-2\). Option D does not result from dividing both terms by the same common factor. Memory cue: “outside factor × inside remainder” must reproduce every original term; multiply \(7a(a-2)\) to check.