यदि \(f:R\to R\), (f(x)=|x-4|+1), तो परास क्या होगा?

If \(f:R\to R\), (f(x)=|x-4|+1), what is the range?

Explanation opens after your attempt
Correct Answer

A. \([1,\infty\))

Step 1

Concept

\(|x-4|\ge0\) for every real (x).

Step 2

Why this answer is correct

Therefore \(|x-4|+1\ge1\).

Step 3

Exam Tip

At (x=4), the minimum value (1) is obtained, so the range is \([1,\infty\)). चरण 1: \(|x-4|\ge0\) हर वास्तविक (x) के लिए। चरण 2: इसलिए \(|x-4|+1\ge1\)। चरण 3: (x=4) पर न्यूनतम मान (1) मिलता है, अतः परास \([1,\infty\)) है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(f:R\to R\), (f(x)=|x-4|+1), तो परास क्या होगा? / If \(f:R\to R\), (f(x)=|x-4|+1), what is the range?

Correct Answer: A. \([1,\infty\)). Explanation: चरण 1: \(|x-4|\ge0\) हर वास्तविक (x) के लिए। चरण 2: इसलिए \(|x-4|+1\ge1\)। चरण 3: (x=4) पर न्यूनतम मान (1) मिलता है, अतः परास \([1,\infty\)) है। / Step 1: \(|x-4|\ge0\) for every real (x). Step 2: Therefore \(|x-4|+1\ge1\). Step 3: At (x=4), the minimum value (1) is obtained, so the range is \([1,\infty\)).

Which concept should I revise for this Mathematics MCQ?

\(|x-4|\ge0\) for every real (x).

What exam hint can help solve this Mathematics question?

At (x=4), the minimum value (1) is obtained, so the range is \([1,\infty\)). चरण 1: \(|x-4|\ge0\) हर वास्तविक (x) के लिए। चरण 2: इसलिए \(|x-4|+1\ge1\)। चरण 3: (x=4) पर न्यूनतम मान (1) मिलता है, अतः परास \([1,\infty\)) है।